Question

(OR)
) Find the co-ordinates of the points of trisection of the line segment joining the points
3, 3) and (3, – 3)
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Answer 1

Answer:

Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then 

(x,y)=(m+nmx2+nx1,m+nmy2+ny1)

Let P (x1,y1) and Q (x2,y2) are the points of trisection of the line segment joining the given points i.e., AP = PQ = QB

Therefore, point P divides AB internally in the ratio 1:2.

x1 = 1+21(3)+2(−3)

y1 = 1+21(−3)+2(3)

x1 = 33−6=−1

y1 = 3−3+6=1

Therefore, p(x1

hope it help you