Question

OR
Find two consecutive odd positive integers, sum of whose squares is 290.
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Answer 1

Step-by-step explanation:

Let x an odd positive integer

Then, according to question

x2+(x+2)2=290

2x2+4x−286=0

x2+2x−143=0

x2+13x−11x−143=0

(x+13)(x−11)=0

x=11 as x is positive

Answer 2

let x be that number

x²+x²=290

2x²=290

2x=√290

x= 8.514693182