Question

OR
For what value of k does the pair of equations is given below has infinitely many solutions
kx + 3y - (k - 3) = 0
12x + ky - k = 0
Ans: Here a = k b1 = 3,
C1 = k-3
b2 = k,
C2 =k
Here
21
b1
a
02
뜨
For a pair of linear equation to have infinitely many solutions 1
A2 = 12
K
3
k-3
.
12
b2
k
C2
k
02
b2
C2
k
3 k-3
So we need
12 k
k
k
3
Or
12 k
K = 36
k=V36 = +6
3 k-3
Also
k k
K2 - 3k = 3k
6k = k?
K= 0 or k= 6
plz tell me step by step plz brother and sisters ​

Answer 1

Answer:

I don't know it sorry brother I am so sorry to say this