OR
From the following distribution, find the median :
Classes : 500 - 600 600 – 700 700 - 800 800 - 900 900 - 1000
Frequency: 36 | 32 | 32 | 20
30
Answers
Answer:
Median = 721.875
Step-by-step explanation:
We are given the following frequency distribution;
Classes Frequency (f) Cumulative frequency (cf)
500 - 600 36 36
600 - 700 32 68
700 - 800 32 100
800 - 900 20 120
900 - 1000 30 150
∑f = 150
Firstly, we will calculate , (where N = ∑f), = = 75.
So, the value of cumulative frequency just greater than or equal to 75 is 100.
Therefore, median class is 700 - 800 .
Now, Median formula =
where, = lower limit of median class = 700
N = ∑f = 150
= frequency of median class = 32
cf = cumulative frequency just above the median class = 68
c = width of class interval = 100
So, Median =
= = 700 + 21.875 = 721.875
Therefore, Median of given distribution is 721.875 .
Step-by-step explanation:
Median = 721.875
Step-by-step explanation:
We are given the following frequency distribution;
Classes Frequency (f) Cumulative frequency (cf)
500 - 600 36 36
600 - 700 32 68
700 - 800 32 100
800 - 900 20 120
900 - 1000 30 150
∑f = 150
Firstly, we will calculate \frac{N}{2}
2
N
, (where N = ∑f), \frac{N}{2}
2
N
= \frac{150}{2}
2
150
= 75.
So, the value of cumulative frequency just greater than or equal to 75 is 100.
Therefore, median class is 700 - 800 .
Now, Median formula = x_L + \frac{\frac{N}{2} -cf}{f_m}*cx
L
+
f
m
2
N
−cf
∗c
where, x_Lx
L
= lower limit of median class = 700
N = ∑f = 150
f_mf
m
= frequency of median class = 32
cf = cumulative frequency just above the median class = 68
c = width of class interval = 100
So, Median = 700 + \frac{\frac{150}{2} -68}{32}*100700+
32
2
150
−68
∗100
= 700 + \frac{7}{32} *100700+
32
7
∗100 = 700 + 21.875 = 721.875