Chemistry, asked by vinaykumarsinghv371, 5 months ago

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Butanol
treated
with sodium.​

Answers

Answered by silver00
1

Answer:

2Na (s) + 2C4H9OH (l) = 2C4H9ONa (l) + H2

Explanation:

2Na (s) + 2C4H9OH (l) = 2C4H9ONa (l) + H2

sodium + butanol = sodium butoxide + hydrogen

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