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How does normal eye achieve accommodation? The given diagram shows the path of a ray of
light through an equilateral prism. Answer the following questions:
2
J3
Q
V4
B
C с
(a) Which is the refracted ray?
(b) Which is the emergent ray?
(c) What name is given to angle 1?
(d) What name is given to angle 3?
(e) What name is given to angle 5?
(1) What is the relation between angles 1, 2, 3 and 4?
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The diagram is shown. The ray PQ enters the prism from the side AB, its angle of incidence is 0°. Thus it does not undergo any refraction. Its angle of refraction is also 0°. When this light ray reaches the base of the prism (BC), its angle of incidence (on the boundary BC) is 60° which is more than its critical angle (42°). Thus this incident light ray (QR) does not enter into the next medium, instead it undergoes total internal reflection. When this reflected light ray (RS) reaches the side AC, its angle of incidence is 0°. Again, it does not undergo any refraction, which causes the angle of emergence to become 0°.
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