Math, asked by 91Nishant, 28 days ago

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If sin(A + B) = 1 and cos( A - B) = 1,0° < A + B < 90°, A>B
find A and B

Answers

Answered by sonurohan85
1

Step-by-step explanation:

sin (A + B)= 1 or sin (A + B) = sin 90° [As sin 90° = 1] A + B = 90° …(1) Again, Cos(A-B) = 1 = cos 0° A – B = 0 …(2) Adding (1) and (2), we get 2A = 90° or A = 45° Putting A = 45° in (1) we get 45° + B = 90° or B = 45° Hence, A = 45° and B = 45°.Read more on Sarthaks.com - https://www.sarthaks.com/711894/if-sin-a-b-1-and-cos-a-b-1-0-a-b-90-and-a-b-then-find-a-and-b?show=711896#a711896

Answered by bilashg626
0

Answer:

A=B=π/4

Step-by-step explanation:

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