Math, asked by urmilakumari933412, 4 months ago

or next 4 hours.
4. Two trains travel in opposite directions at 36 km/hr and 45 km/hr and a man
sitting in slower train passes the faster train in 8 seconds. The length of
(4) 12 km/hr
(1) 10K
5 km/hr
(S. S. C.)
a ofn
(2) 100 m
(3)120 m​

Answers

Answered by riyaenterprises012
1

Step-by-step explanation:

As the trains travel in opposite direction then

Relative speed=(45+36)km/hr=(81×

18

5

)m/sec=(

18

405

)m/sec

∴ length of the faster train=

18

405

×8=180m

Answered by kavitakaur1511155555
0

Answer:

Relative speed of slower train w.r.t fast train is : v = 36+45 = 81 kmph = 22.5 m/s

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