Question

or potential A of an electric dipole is determined by the current flowing in the wire connecting the charge​

Answer 1

Answer:

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Answer 2

Explanation:

5.1. The Magnetic Field

Consider two parallel straight wires in which current is flowing. The wires are neutral and

therefore there is no net electric force between the wires. Nevertheless, if the current in both

wires is flowing in the same direction, the wires are found to attract each other. If the current in

one of the wires is reversed, the wires are found to repel each other. The force responsible for

the attraction and repulsion is called the magnetic force. The magnetic force acting on a moving

charge q is defined in terms of the magnetic field:

F magnetic = q( ) v ¥ B

The vector product is required since observations show that the force acting on a moving charge

is perpendicular to the direction of the moving charge. In a region where there is an electric field

and a magnetic field the total force on the moving force is equal to

F total = F electric + F magnetic = qE + q( ) v ¥ B

This equation is called the Lorentz force law and provides us with the total electromagnetic

force acting on q. An important difference between the electric field and the magnetic field is

that the electric field does work on a charged particle (it produces acceleration or deceleration)

while the magnetic field does not do any work on the moving charge. This is a direct

consequence of the Lorentz force law:

dWmagnetic = F magnetic ∑ dl = q[ ] ( ) v ¥ B ∑ v dt = 0

We conclude that the magnetic force can alter the direction in which a particle moves, but can

not change its velocity.

Example: Problem 5.1

A particle of charge q enters the region of uniform magnetic field B (pointing into the page).

The field deflects the particle a distance d above the original line of flight, as shown in Figure

5.1. Is the charge positive or negative? In terms of a, d, B, and q, find the momentum of the

particle.

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