Question

or the post of 2 receptionist,there are 12 equally qualified candidates.in how many ways they can be selected

Answer 1

12C2 = 12 !/2! (12 - 2)!

        =12 * 11 * 10!/2! 10!

        = 12 * 11/2

        = 66 ways

where C is Combination.If you have learned this in school in Permutations and Combinations

Happy Learning :)

Answer 2

Answer:

66

Step-by-step explanation:

Total candidates = 12

No. of posts = 2

We will use combination for no. of possible ways of selecting 2 candidates.

Formula : $^nC_r=\frac{n!}{r!(n-r)!}$

n = 12

r = 2

Substitute the values

$^{12}C_{2}=\frac{12!}{2!(12-2)!}$

$^{12}C_{2}=\frac{12 \times 11 \times 10!}{2!(10)!}$

$^{12}C_{2}=\frac{12 \times 11}{2!}$

$^{12}C_{2}=66$

Hence there are 66 possible ways of selecting two candidates .