Question

or triangle ABC,A(cos x,sin x);B(cos y,sin y);C(cos z,sin z) the circumcentre is (0,0).then find the orthocentre where ,0≤x≤π/2;0≤y≤π/2;0≤z≤π/2 and cos x+cos y+cos z= (1+√3)/2

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Answer 1

Answer:

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Answer 2

Answer:

answer for the given problem is given