orange cost ₹54 for three dozen in supermarket. what is the cost of eight orange solve by direct and inverse variation
Answers
Answered by
53
Cost(in Rs.) No. of oranges
54 36
x 8
(Directly proportionate to each other)
(Cross multiply)
x*36=54*8
x =54*8/36
x =12
Ans.=The cost of 8 oranges is Rs. 12.
54 36
x 8
(Directly proportionate to each other)
(Cross multiply)
x*36=54*8
x =54*8/36
x =12
Ans.=The cost of 8 oranges is Rs. 12.
Answered by
13
1 dozen is equal to 12
the cost of 36 oranges is equal to 54
then the cost of 1orange is equal to 54/36
the cost of 8oranges is equal to 54/36*8
then by solving it we get the cost of 8 oranges is 12 in supermarket.
the cost of 36 oranges is equal to 54
then the cost of 1orange is equal to 54/36
the cost of 8oranges is equal to 54/36*8
then by solving it we get the cost of 8 oranges is 12 in supermarket.
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