Question

Orange light of wavelength is 6600 angstrom traveling in air gets refracted in water. light in air is 3× 10 to the power 8 and refractive index 4/3. Find the frequency of light in air. speed of light in water.
Wavelength of light in water​

Answer 1

Given; refractive index of water = 4/3

speed of light = 3× 10 ^ 8 m/ s

by using Smells law ;

n = c/v

4/3 = 3×10 ^ 8 / v

4 v =. 3 ( 3 × 10 ^8 )

v = 9 × 10^ 8 ÷ 4

= 2.25 × 10 ^ 8 m/s ( speed of light in water )

v2 = c/v

1.0003 = 3 × 10^ 8 / v

v × 1.0003 = 3 × 10 ^ 8

v = 3 × 10 ^ 8 /. 1.0003

v = 2.999100269 × 10^ 8 m/ s ( speed of light in air )

Answer 2

Answer:

The speed of light in water is $2.25*10^{8}m/s$.

The wavelength of light in water is 4950Å.

The frequency of light in air is $4.5*10^{14} Hz$.

Explanation:

Given,

Wavelength of orange light is 6600 Å.

Speed of light in air is $3*10^{8}$m/s

Refractive index of water is $\frac{4}{3}$.

We know that, the refractive index in a medium is defined as the ratio of speed of light in air to the speed of light in the medium.

$n=\frac{c}{v}$

$\frac{4}{3}=\frac{3*10^{8} }{v}$

$v=\frac{9*10^{8} }{4}=2.25*10^{8}m/s$

The relation between speed and frequency can be written as

$speed=wavelength*frequency$

The frequency of light remains constant as the frequency of light doesn't change while moving from one medium to other. The frequency of light in air will be the same as the frequency of light in water.

$v=$λ$*f$

So we get $v$∝λ

Wavelength of light in water will be $Wavelength_{water}= Wavelength_{air}*\frac{ v_{water} }{v_{air} }$

$Wavelength_{water}= 6600*\frac{2.25*10^{8} }{3*10^{8} }$

$Wavelength_{water}= 6600*0.75=4950$

Therefore the wavelength of light in water is 4950Å and the sped of light in water is $2.25*10^{8}m/s$.

The frequency of light in air is $\frac{speed}{wavelength}$

$f_{air} =\frac{3*10^{8} }{6600*10^{-10}m }$

$f_{air} =4.5*10^{14} Hz$

To know more about refractive index go to the following link.

https://brainly.in/question/26146905

To know more about frequency go to the following link.

https://brainly.in/question/1118329

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