Orbit of an artifical satellite at distace of 42260Km from earth is
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The orbit of an artificial satellite in a circular uniform orbit
orbit = circumference / time
= 2 * pi * r / t
given
r= 42600 km time = 24 hour
v = 2*3.14 * 42260 / 4
velocity (linear speed)=11058.3 km/hr
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