Question

Orbit of an artificial satellite at a distance of 45000km from earth is circular.It completes one revloution around the earth in 24hrs.Its linear speed is​

Answer 1

Distance covered by the satellite in 24 hours

s=2πr

=2×3.14×42250=265464.58 km

Therefore speed of satellite,

v=

time taken

distance travelled

=

24×60×60

265464.58

=3.07 km s

−1