Question

Orbital angular momentum value of an electron in H-atom for 4d orbital is​

Answer 1

Answer:

4 multiply by 10^-34 (apx.)

Explanation:

angular momentum = no. of orbit multiply by   h/2pi

4d is in 4th orbit

Answer 2

Orbital angular momentum value of an electron in H-atom for 4d orbital is​ $4\frac{h}{2\pi }$.

• Bohr's theory of the atomic model states the angular momentum of an electron.

• Following Bohr's theory for hydrogen-like atoms (single electron species), the angular momentum (mvr) should be an integral multiple of $\frac{h}{2\pi }$

• m v r =  $n\frac{h}{2\pi }$

Here, m= mass of electron

           v = velocity

          r = radius of the nth orbit

          n= Principal Quantum Number of the electron

         h= Planck's constant

• In the given question, the electron is in 4d orbital Hence principal quantum number = 4