Physics, asked by Nabhonil4947, 1 year ago

Order of magnitude of density of uranium nucleus is $(m_{p}=1.67\times 10^{-27}\ kg)$ (a) 10²⁰ kg / m3(b) 10¹⁷ kg / m3(c) 10¹⁴ kg / m3(d) 10¹¹ kg / m3

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The mass of 2mcube of steel is 15600 kg.calculate the density of steel in S.I unit .

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Order of magnitude of density of uranium nucleus is (a) 10²⁰ kg / m3(b) 10¹⁷ kg / m3(c) 10¹⁴ kg / m3(d) 10¹¹ kg / m3

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Order of magnitude of density of uranium nucleus is $(m_{p}=1.67\times 10^{-27}\ kg)$ (a) 10²⁰ kg / m3(b) 10¹⁷ kg / m3(c) 10¹⁴ kg / m3(d) 10¹¹ kg / m3