Question

Order of magnitude of period of rotation of earth about its own axis is ...​

Answer 1

Answer:

86400 sec = $0.864$ × $10^{5}$ sec

Therefore order of magnitude is 5.

Explanation:

When you write value in the form of $A\times10^n$ where $0.5\leq A > 5$ then $n$ is called as order of magnitude of that value.