Ordinary chlorine has two isotopes :35Cl17 and 37Cl17 in the ratio 3:1.Calculate the relative atomic mass of chlorine?? Quick plz anybody
Answers
Answered by
117
Chlorine has two isotopes namely ³⁵Cl and ³⁷Cl
³⁵Cl:³⁷Cl=3:1
Let the relative abundance of ³⁵Cl be 3x % and ³⁷Cl be x %
3x+x=100⇒4x=100⇒x=25
Relative abundance of ³⁵Cl=3×25=75%
Relative abundance of ³⁷Cl=25%
Atomic mass of chlorine=(75/100×35)+(25/100×37)
=105/4+37/4=142/4=35.5 u(Ans.)
Answered by
26
Given:
Isotope one = 35Cl17
Isotope two = 37Cl17
To Find:
Relative atomic mass of chlorine
Solution:
Average atomic mass = relative abundance of 37Cl isotope × atomic mass of 37Cl isotope + relative abundance of 35Cl isotope × atomic mass of 35Cl isotope
= (37 X 0.25) + (35 X 0.75)
= 9.25 + 25.25
= 35.5 u
Answer: The relative atomic mass of chlorine is 35.5u.
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