Question

Ordinary water containsone part of heavy water per 6000 parts of water by weight. The number of heavy water molecules present in a drop of water of volume 0.01 ml is

Answer 1

Answer:

6000g ------1g

0.01g---------?

1.6×10^-6 g

heavy water ---D20

20g'-----6×10^23

1.6×10^-6 ----

1 part of D2o --- 6000 parts of H2O

6000g D2o -------1g of H2O

x----------------0.01

please find x

Explanation:

Answer 2

Answer:

no. of molecules of H2O = 0.01 / 18 × 6000 NA

= 20/3 NA

= 6.66 NA.