Question

Orientation of two identical small bar magnet of magnetic moment 'M is as shown in figure. The magnitude of magnetic field at the point o which lies on equatorial line of one magnet and axial line of another magnet is (r >> size of magnet) [NCERT Pg. 177] SIN I S MOM (1) (2) узим 4nr3 4023 √5 MOM (3) (4) 2719 MOM 2nr 3 45r3​

Answer 1

Given: M=10Am

2

Solution: When two identical short bar magnets are placed such that their axes are perpendicular to each other then that point will be axial position for first bar magnet and equatorial for another.

Formula used for magnetic field at axial position will be:

B

1

=

4π

μ

0

×

r

3

2M

Now, put values in the formula

B

1

=10

−7

×

(0.05)

3

2×10

=0.016

Formula used for magnetic field at equatorial position will be:

B

2

=

4π

μ

0

×

r

3

M

Now, put values in the formula

B

2

=10

−7

×

(0.05)

3

10

=0.008

Net magnetic field=

B

1

2

+B

2

2

B=1.8×10

−2

PLEASE MARK AS BRAINLIEST