origin is shifted to the point (- 3, 4)without changing the direction of the axes. then the equation of the line 3 x _ 4 _ 7 = 0 in the new system is
Answers
Answered by
27
put X=x-3
and Y = y+4
in the eqn to get new eqn
3(x-3)-4(y+4)-7=0
3x-4y-9-16-7=0
3x-4y-32=0
and Y = y+4
in the eqn to get new eqn
3(x-3)-4(y+4)-7=0
3x-4y-9-16-7=0
3x-4y-32=0
Answered by
24
Origin is shifted to the point (- 3, 4)without changing the direction of the axes. then the equation of the line 3 x _ 4 _ 7 = 0 in the new system is 3x-4y+32=0
Attachments:
Similar questions