Question

original number.
3. The sum of a number of 2 digits and of the number formed by reversing the digits is 110, and the difference
of the digits is 6. Find the number.
4. A certain number between 10 and 100 is 8 times the sum of its digits, and if 45 be subtracted from it th
digits will be reversed. Find the number.​

Answer 1

Answer:

3) 28 and 82

4) 72

Step-by-step explanation:

3) since the last digit of the sum is zero, the numbers in the last digit can be :

1 and 9

2 and 8

3 and 7

4 and 6

5 and 5

Another condition given is the difference of digits is 6. So the two digits should be 2 and 8

So the two digits numbers will be 28 and 82

28+82= 110

4) 8(x+y)=10x+y

10x+y-45=10y+X

9x-45=9y

x-5=y-------equation (1)

8x+8y=10x+y

7y=2x-------equation (2)

Multiply equation (1) by 2

2x-10=2y

But 2x= 7y

So 7y-10=2y

5y=10

y=2

x=7

So answer is 8(7+2)=72