Question

orrect answer.
(i) If the solubility of Pbl, in water is x g mole per litre, then its solubility product
given by
(a) x?
(b) 2x2
(c) 4x2
3
(d) 4x
​

Answer 1

Answer:

PbI2⇌Pb2++2I−

                  x        2x 

given solubility of PbI2 is 0.7Lg

also, molar mass of PbI2=461.2g/mol

⇒[PbI2]=461.20.7mol/Litre=1.5×10−3

solubility product, Ksp=x(2x)2

Ksp=4x3

Ksp=4(1.5×10−3)3

∴ Solubility product of PbI2=135×10−9mol2/lit2

Explanation:

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