Question

Orthoboric acid –
(a) donate proton to form H₂BO₃⁻
(b) accept proton of form H4BO₃⁺
(c) donate OH– to form H₂BO₂⁺
(d) accept OH– to form [B(OH)₄]⁻

Answer 1

Answer:

option C.

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Answer 2

(d) accept OH– to form [B(OH)₄]⁻

Explanation:

Ortho boric acid does not donate proton, like most of the acids but rather it accepts OH-.  

B(OH)3 + 2H2O ----> H3O+ + B(OH4)-

Boric acid reacts with water and accepts OH ion to form B(OH4)-, which behaves as a weak acid.

Option D is the answer.