Orthocentre of triangle with vertices (0,5), (12, 0) and (12,5) is :
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To find orthocentre of the triangle formed by (0,0),(3,4) and (4,0)
Let H be the orthocenter of △OAB
Therefore (slope of OP i.e OH).(slope of BA)=−1
⇒(
3−0
y−0
).(
3−4
4−0
)=−1⇒−
3
4
y=−1⇒y=
4
3
Therefore required orthocenter =(3,y)=(3,
4
3
)
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