orthogonal trajectories (x^2+y^2-ay)=0
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Step-by-step explanation:
Here, x2 + y2 − ay = 0 Differentiating w.r.t. x, we get This is the differential equation of the circles. The equation of orthogonal trajectories is Therefore, x(1 + v2) = c ⇒ x(1 + y2/x2) = c ⇒ x2 + y2 = cxRead more on Sarthaks.com - https://www.sarthaks.com/563876/find-the-orthogonal-trajectories-of-the-circles-x-2-y-2-ay-0-where-a-is-a-parameter
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