Question

os/ResponsePage.aspx?idolw2wmlkkSxLBUEGRP Stazzgo
6
A5 m long ladder weighing 300 N rests on a floor and against a wall. The ladder makes a 600
angle with the ground. For all contact surfaces the coefficient of friction is 0.2. The center of
gravity of the ladder is at a distance of 2m from point B. A man weighing 600 N moves up the
ladder. Find the distance he covers when the ladder slips.
А
5 m
of
60
Od = 1.786 m
Od 2.786 m
Widgets
O d = 3.786 m

Answer 1

Answer:

m

of

60

Od = 1.786 m

Od 2.786 m

Widgets

O d = 3.786 m