Question

Osmotic preesure of a solution contain 3.5 g of dissolve protein per 50cc of a solution is 25 mm hg at 37 degree c. Calulate molar mass of protein

Answer 1

Answer:

Explanation:

m2, Dissolved protein =3.5gVolume =50cc =50mL =0.05 Lπ, Osmotic Pressure =25mmHg or 25760atmTemperature =37oC =310KMolar mass of protein =?π=n2RTV or m2RTM2VR=gas constant =0.082 Latm/K/molM2 is the molar mass of soluteSubstituting the valuesM2=3.5×0.082×310×7600.05×25=54093.6 g/mol

Answer 2

Answer:

723333g/mol

Explanation:

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