Osmotic pressure of 5% solution of sucrose at 15°c
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osmotic pressure= concentration×R×Temperature
Here solution is 5% i.e 5g of sucrose is dissolved in 100ml of solvent
concentration=(5÷342)÷0.1
R=0.0821
T=15+273=288
substitute the values and get the answer
Here solution is 5% i.e 5g of sucrose is dissolved in 100ml of solvent
concentration=(5÷342)÷0.1
R=0.0821
T=15+273=288
substitute the values and get the answer
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