Chemistry, asked by nikraghav867, 11 months ago

Osmotic pressure of a 0.1m monobasic acid having a ph of 2 at 25ºc is

Answers

Answered by smookyqueen
5

Osmotic pressure (π)=iCRT(π)=iCRT

Where CC=Molarity of solution

α=i−1m−1α=i−1m−1

0.1=i−12−10.1=i−12−1

i = 1.1

∴π=iCRT∴π=iCRT

∴=1.1×0.1RT=0.11RT

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