Osmotic pressure of a solution containing 7.0g of a solute per 100ml of it is found to be 25 mmhg at 37°c. calculate the molar mass of the solute. (r= 8.314/kj/mol)
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Answer:
Osmotic pressure = Conc.(Molarity)*R*T(in k)
Explanation:
Let the molar mass = x
Thus molarity is 7/0.1x
Osmotic Pressure = 7/0.1x * 8.314 * 310
We know that Osmotic Pressure is 25 mmhg
25 = 18041.38/0.1x
0.1x = 18041.38/25
x = 18041.38/2.5
Thus molar mass = 7,216.552 g/mol
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