Question

Osmotic pressure of a solution containing 7 gram of a protein in 100 ml of solution is 20 mm HG at 37 degree Celsius calculate the molecular mass of the protein

Answer 1

Osmotic pressure, π= cRT

π = mRT/V*M
where m is mass of protien,
V is volume of solution = 100mL = 0.1L
P = 20mmHg = 20/760 atm

20/760 = 7*0.082*310/0.1*M

Therefore, M = 67617.2 g/mol

Answer 2

Hey buddy,

● Answer -
M = 67698 g

● Explaination -
# Given -
W = 7 g
M = ?
V = 100 ml = 10^-4 m^3
T = 37°C = 310 K
P = 20 mm Hg = 2.666×10^3 Pa

# Solution -
According to ideal gas eqn -
PV = nRT
2.666×10^3 × 10^-4 = n × 8.314 × 310
n = 0.2666 / (8.314×310)
n = 1.034×10^-4 mol

Molecular mass of protein -
M = W / n
M = 7 / 1.034×10^-4
M = 67698 g

Therefore, molecular mass of given protein is 67698 g.


Hope this helps you...