Question

Osmotic pressure of a solution is 0.0821 atm at a temperature of 300 K. The concentration in moles/litre will be
(a) 0.33
(b) 0.666
(c) 0.3 × 10-2
(d) 3

Answer 1

Osmotic pressure = C x R x T

where C = concentration in moles / litre

R = universal gas constant = 0.0821 atm lit mole⁻¹ K⁻¹

T = Temperature in kelvin = 300K

0.0821 = C x 0.0821 x 300

C = 1/300

C = 0.3 x 10⁻² moles/litre

Hope it helps!

Answer 2

Answer:

The concentration of the solution that exerts osmotic pressure of 0.0821 atm at 300K is 0.3 × 10⁻² moles/litre.

Explanation:

What is Osmotic pressure?

• Osmotic pressure may be defined as the hydrostatic pressure applied in a reverse direction that just stops osmosis.
• It is a type of colligative property, i.e., the property is dependent upon the moles of solute dissolved in the solution at a particular temperature and not upon the chemical nature of the solution.

Mathematically, it can be represented as:

π = CRT
where,
π = osmotic pressure of the solution
C = concentration of solute in the solution expressed in moles/litre [n/V]
R = universal gas constant = 0.0821 Latm.K⁻¹.mol⁻¹
T = Temperature of the system in Kelvin (K)

Calculation:

Given,
T = 300K
R = universal gas constant = 0.0821 Latm.K⁻¹.mol⁻¹ [understood]
π = 0.0821
Let C = x

∴ By the problem,

0.0821 = x × 0.0821 × 300
⇒ x = 1/300 = 0.3 × 10⁻² moles/litre

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