OT (vii) The emf of the cell balances against a length of 217 cm of potentiometer wire. When the cell is shunted by a resistan of 151, the balancing length is 200 cm. Find the inter B) resistance of the cell.
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Answer:
The internal resistance of cell is given by :-
r=(
12
4
−1)R (l
1
: balance length without shunt
l
2
: balance length with shunt
R: connoted shunt in series with cell)
⇒r=(
100
150
−1)×2
=(1.5−1)×2=1Ω (Ans)
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