Question

Other two zeroes of x⁴ – 3x³ + 6x – 4, if two of its zeroes are √2 and -√2 2,1 -1,-2 1,-2 -2,1 none of the above other:

Answer 1

if two zeroes are √2 and -√2 THEN .

(x+√2)(x-√2)

as (a square -b square)

as (x square -2)

on dividing x square -2 with x^4-3x cube +6 x -4 we get quotient = x square -3x-2. & remainder = -8

we know that if remainder is0 and quotient is something then the quotient is in equation but in this case we get remainder also so, the others zeros are not possible.

as well as the answer is none of the above.

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