Other two zeroes of x⁴ – 3x³ + 6x – 4, if two of its zeroes are √2 and -√2 2,1 -1,-2 1,-2 -2,1 none of the above other:
Answers
Answered by
1
if two zeroes are √2 and -√2 THEN .
(x+√2)(x-√2)
as (a square -b square)
as (x square -2)
on dividing x square -2 with x^4-3x cube +6 x -4 we get quotient = x square -3x-2. & remainder = -8
we know that if remainder is0 and quotient is something then the quotient is in equation but in this case we get remainder also so, the others zeros are not possible.
as well as the answer is none of the above.
HOPES ITS HELP U MARK IT AS A BRAINLIST ANSWER . FOLLOW ME AND RATE THIS ANSWER .
SAFE FROM CORONA .......
AND SAFE TO OTHERS .....
STAY HOME AND LIVE BEHIND THE LAKSHAMAN REKHA .
Similar questions