ÔÞkÏÞkLke {ËËÚke rðÄuÞLkwt
x «íÞu rðfr÷ík {u¤ðku : cos(
x2
+ 1)
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Solution. Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR. Given: BC = 9, AB = 5, PQ = 6 and QR = 10. Hence, Ratio of Area of △ABC : Area of △PQR = 3: 4.
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