Oto > 0, reaction favolls POL
Delta > , reaction favours products formation
on the stron configuration 1s 2s 2p represents an atom of:
* Omelum
в Oxygen
O Carbon
Hydrogen
Answers
Answer:
The initial partial pressures of CO and CO
2
are 1.40 atm and 0.8. atm respectively.
The expression for the reaction quotient is :
Q
p
=
P
CO
P
CO
2
=
1.4
0.80
=0.571
As the value of the reaction quotient is greater than the value of the equilibrium constant, the reaction will move in the backward direction.
To attain the equilibrium, the partial pressure of CO
2
will decrease and the partial pressure of CO will increase.
Let p atm be the decrease in the partial pressure of CO
2
. The increase in the partial pressure of CO will be p atm.
The equilibrium partial pressure of CO
2
is 0.80-p atm.
The equilibrium partial pressure of CO is 1.4 + p atm.
The equilibrium constant is:
K
p
=
P
CO
P
CO
2
=
1.4+p
0.80−p
=0.265
0.265(1.4+p)=0.80−p
0.371+0.265p=0.80−p
p=0.339 atm
The equilibrium partial pressure of CO is 1.4+0.339=1.739.
The equilibrium partial pressure of CO
2
is 0.80−0.339=0.461 atm.