Question

OU
A and B can do a piece of work in 12 days, C and A in 20 days and B and C
in 15 days, then in how many days will they finish it working together?​

Answer 1

Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$a + b \: in \: one \: day = \frac{1}{12} \\ b + c \: in \: one \: day = \frac{1}{15} \\ c + a \: in \: one \: day \: = \frac{1}{15} \\ \\ a + b + c + a + c + b = \frac{1}{12} + \frac{1}{15} + \frac{1}{20} \\ 2(a + b + c) = \frac{5 + 4 + 3}{60} \\ 2(a + b + c) = \frac{12}{60} = \frac{1}{5} \\ a + b + c = \frac{1}{2 \times 5} = \frac{1}{10} \\ \\ a,b \: and \: c \: together \: can \: do \: the \: work \: in \: 10 \: days$

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