ou. Ratio and pooportion
pôractice Set 4.1
1 from the following pans of numbers, find the
reduced form of ratio of first number to second
nomber
Answers
Answer:
ath Chapter 4 - Ratio And Proportion
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Textbook Solutions Class 9 Math Ratio And Proportion
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Page No 61:
Question 1:
From the following pairs of numbers, find the reduced form of ratio of first number to second number.
(i) 72, 60 (ii) 38, 57 (iii) 52, 78
ANSWER:
(i)
72 : 60 =
72
60
=
72÷12
60÷12
=
6
5
= 6 : 5 (HCF of 72 and 60 = 12)
Thus, the reduced form of 72 : 60 is 6 : 5.
(ii)
38 : 57 =
38
57
=
38÷19
57÷19
=
2
3
= 2 : 3 (HCF of 38 and 57 = 19)
Thus, the reduced form of 38 : 57 is 2 : 3.
(iii)
52 : 78 =
52
78
=
52÷26
78÷26
=
2
3
= 2 : 3 (HCF of 52 and 78 = 26)
Thus, the reduced form of 52 : 78 is 2 : 3.
(ii)
38 : 57 =
38
57
=
38÷19
57÷19
=
2
3
= 2 : 3 (HCF of 38 and 57 = 19)
Thus, the reduced form of 38 : 57 is 2 : 3.
(iii)
52 : 78 =
52
78
=
52÷26
78÷26
=
2
3
= 2 : 3 (HCF of 52 and 78 = 26)
Thus, the reduced form of 52 : 78 is 2 : 3.
Page No 61:
Question 2:
Find the reduced form of the ratio of the first quantity to second quantity.
(i) 700 rs, 308 rs (ii) 14 rs, 12 rs. 40 paise. (iii) 5 litre, 2500 ml (iv) 3 years 4 months, 5years 8 months (v) 3.8 kg, 1900 gm
(vi) 7 minutes 20 seconds, 5 minutes 6 seconds.
ANSWER:
(i)
Rs 700 : Rs 308 =
700
308
=
700÷28
308÷28
=
25
11
= 25 : 11 (HCF of 700 and 308 = 28)
(ii)
14 rupees = 1400 p
12 rupees 40 paise = 1200 + 40 = 1240 p
∴ 14 rupees : 12 rupees 40 paise = 1400 p : 1240 p =
1400
1240
=
1400÷40
1240÷40
=
35
31
= 35 : 31 (HCF of 1400 and 1240 = 40)
(iii)
5 litre = 5000 mL (1 L = 1000 mL)
∴ 5 litre : 2500 mL = 5000 mL : 2500 mL =
5000
2500
=
5000÷2500
2500÷2500
=
2
1
= 2 : 1 (HCF of 5000 and 2500 = 2500)
(iv)
3 years 4 months = 3 years + 4 months = 3 × 12 + 4 = 36 + 4 = 40 months (1 year = 12 months)
5 years 8 months = 5 years + 8 months = 5 × 12 + 8 = 60 + 8 = 68 months
∴ 3 years 4 months : 5 years 8 months = 40 months : 68 months =
40
68
=
40÷4
68÷4
=
10
17
= 10 : 17 (HCF of 40 and 68 = 4)
(v)
3.8 kg = 3.8 × 1000 = 3800 g (1 kg = 1000 g)
∴ 3.8 kg : 1900 g = 3800 g : 1900 g =
3800
1900
=
3800÷1900
1900÷1900
=
2
1
= 2 : 1 (HCF of 3800 and 1900 = 1900)
(iv)
7 minutes 20 seconds = 7 minutes + 20 seconds = 7 × 60 + 20 = 420 + 20 = 440 seconds (1 minute = 60 seconds)
5 minutes 6 seconds = 5 minutes + 6 seconds = 5 × 60 + 6 = 300 + 6 = 306 seconds
∴ 7 minutes 20 seconds : 5 minutes 6 seconds = 440 seconds : 306 seconds =
440
306
=
440÷2
306÷2
=
220
153
= 220 : 153 (HCF of 220 and 153 = 2)
Step-by-step explanation:
u also surch on gugle .... ...
Answer:
first part 4:1+4×1=4:5
second part 1:4+1×1=1:5