Question

Ouestion 40 please give urgent

Answer 1

Given sides of a triangle are x,x + 1, 2x + 1.

We know that semi-perimeter of a triangle = x + x + 1 + 2x + 1/2

                                                                        = 4x + 2/2
 
                                                                        = 2x + 1.


Given that area of triangle = xroot 10.

We know that Area of triangle = $\sqrt{s(s-1)(s-b)(s-c)}$

                        $x \sqrt{10} = \sqrt{2x + 1(2x + 1 - x)(2x + 1 - (x + 1))(2x + 1 - (2x + 1))}$


                     $x \sqrt{10} = \sqrt{2x + 0}$

                     $x \sqrt{10} = \sqrt{2x}$

                   x = 1/5,0.


Hope this helps!