Oula is going on an outdoor expedition with his family. The expedition will include a hunting event a fishing event a hiking event and a camping event. There are 4 hunting 7 fishing 6 hiking and 3 camping events for oulas family to choose from. How many different outdoor expeditions are possible.
Answers
Given:
Family is going for 1 hunting event + 1 fishing event + 1 hiking event + 1 camping event.
Choices of hunting events = 4
Choices of fishing events = 7
Choices of hiking events = 6
Choices of camping events = 3
To Find:
The number of possible combinations the family can choose from
Solution:
Number of possible combinations
= 4C1 x 7C1 x 6C1 x 3C1
= 4 x 7 x 6 x 3
= 504
Answer: There are a total of 504 combinations to choose from.
GIVEN :
Family is going to have a hunting event ,fishing event ,hiking event , camping event each.
Number of hunting events, fishing events ,. Hiking events , camping events are - 4, 7, 6, 3 respectively.
TO FIND:
The number of possible outdoor expeditions combination that the family can choose .
SOLUTION:
◆Formula for combinations,
nCr = n! /{r!(n - r)!}
◆Number of possible combinations in hunting = 4C1 = 4! /(1!(4-1)!) = 4.
◆Number of possible combinations in fishing = 7 C1
◆Number of possible combinations in hiking = 6C1
◆Number of possible combinations in camping, = 3C1
◆Total number of combinations
By multiplying all the four,
N= 4C1 x 7C1 x 6C1 x 3C1
= 4 x 7 x 6 x 3
= 504.
ANSWER:
There are 504 number of outdoor expedition combinations.