Math, asked by ashokk87073, 4 months ago

ould B
A can do a piece of work in 20 days while B can do it in 15 days. With the help of C, they finish
the work in 5 days. In what time would C alone do it?

Answers

Answered by aadnyagharat
2

A does in one day 1/20 part of the work.

B in one day does 1/15 part of the work.

A+ B together do in one day 1/20+1/15 part of the work= 7/60 part of the work.

A+B+ C do in one day 1/5 part of the work.

C alone does in one day 1/5–7/60 part of the work=[ 5/60 ]part of the work

answer is = 12 days answer

Answered by Anonymous
0

Step-by-step explanation:

A B A+B+C

20 15 5

60

A efficiency = 3

B = 4

C = 12-7

C = 5

C = 60/5

C = 12 days

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