Question

our of 500 car owner invertigated,400 owned car A and 200 owned car B,50 owned both A and B cars. is this data correct
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Answer 1

Answer:

Hey !!

Let U be the set of car owners

investigated. M be the set of persons

who owned car A and S be the set of

persons who owned car B.

Given that,

n (U) = 500, n (M) = 400, n (S)

200 and n (Sn M) = 50

Then,

n(SUM) =n (S) +n (M) - n (Sn

M) = 200+400- 50 = 550

But S UMCUimplies n (S U M) Sn (U).

This is a contradiction. So, the given

data is incorrect.

GOOD LUCK!

Answer 2

Step-by-step explanation:

Let U = set of car owners investigated

M = set of persons who owned car A

S = set of persons who owned car B.

Then n(u) = 500, n(M) = 400, n(S) = 200 and n(S∩M) = 50

∴ n(S∪M) = n(S) + n(M)-n(S∩M) = 200 + 400-50 = 550

But S∪M⊂U⇒n(5∪M)≤n(U)

This is contradiction. So, the given data is incorrect.