Physics, asked by nowfel2117, 9 months ago

Our Sun shines bright with a luminosity of 3.828 x 1026 Watt. Her energy is responsible for many processes and the habitable temperatures on the Earth that make our life possible. (a) Calculate the amount of energy arriving on the Earth in a single day. (b) To how many litres of heating oil (energy density: 37.3 x 106 J/litre) is this equivalent? (c) The Earth reflects 30% of this energy: Determine the temperature on Earth’s surface. (d) What other factors should be considered to get an even more precise temperature estimate? Note: The Earth’s radius is 6370 km; the Sun’s radius is 696 x 103 km; 1 AU is 1.495 x 108 km.

Answers

Answered by Anonymous
1

Given:

Luminosity = 3.828 x 1026 Watt.

Radius of Sun = 696 x 103 km;

Radius of Earth = 6370 km

To Find:

(a) Amount of energy arriving on the Earth in a single day.

(b) To how many litres of heating oil is this equivalent?

(c) The Earth reflects 30% of this energy: Determine the temperature on Earth’s surface.

(d) What other factors should be considered to get an even more precise temperature estimate

Solution:

a) Solar Constant = E0 = L/4πr²

= 3.828 × 10`26/ 4 π( 1.495 . 10`11) ²

= 1.36 × 10 W/m³

Multiplying the amount by the area of Earth cross-section -

E0 = πR² × 86400s  = 1.5 × 10`22J

b) N = E/ 37.3 × 10`6  

= 4 × 10`14  

c) Energy absorbed by earth = πR². ( 1 - A) = 1.2 × 10`17

Therefore,

E0.  πR². ( 1 - A) = 4πR²T`4

T = √E0 ( 1 - A) /4 = 254k

= - 18°c

d) The average Earth temperature is around 15°.  Mostly because of the greenhouse effect, there is incoherence between two values. We should also consider the human energy production, the geothermal heat, and the earth's internal heat.

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