Question

Out of 100 students 40 passed in physics and 30 passed in chemistry if 18 passed in both thw subject,then what is the number of students failed in both subject maths theory behind this problem

Answer 1

52 children failed in both subject s.

Answer 2

Answer:

Number of the student failed in both subjects is 48.

Step-by-step explanation:

Given, Total Number of Student = 100

           Number of student passed in Physics = 40

           Number of student passed in Chemistry = 30

           Number of student passed in both Physics and Chemistry = 18

To find: Number of student failed in both subjects.

Let, P be set of students passed in Physics and c be set of student passed in Chemistry.

then,

n( P ) = 40 , n ( C ) = 30 , n ( P ∩ C ) = 18

Then using the following formula we have,

n( P ∪ C ) = n( P ) + n ( C )  -  n ( P ∩ C )

n( P ∪ C ) = 40 + 30  -  18

n( P ∪ C ) = 52

⇒ Number of student in atleast 1 subject = 52

Number of student Failed in both subject = 100 - 52 = 48

Therefore, Number of the student failed in both subjects is 48.