Question

Out of 100 students in a College, 39 play

Tennis, 58 play cricket, 32 play hockey, 10

play cricket and Hockey, 11 play hockey and

Tennis,13 play tennis and cricket. Determine

(i) just one came (ii) All the three games (iii)

Tennis and cricket but not hockey (Assume

that each student play at least one game)​

Answer 1

Answer:

Tennis=33.5 students

Cricket=46.5 students

Hockey=20 students

Total =100 students

Answer 2

Step-by-step explanation:

Let T ,Cand H be the sets of people who represents tennis cricket and hockey respectively

n(U)=100

n(T)=39

n(C)=58

n(H)=32

n(C intersectionH)=10

n(H intersectionT)=11

n(TIntersection C)=13

Now,

Only T=n(T)-n(T intersection C)

39-13

26

Only H=n(H)-n(H intersectionT)

32-11

21

Only C=n(C)-n(C intersection H)

58-10

48

Atleast one game = only c +only H +only T

48+21+26

95

ii .n(U)=n(T intersection C intersection H)

100

iii.n(T intersection C) = 13