Math, asked by paritarupareliya464, 10 months ago

out of 1000 student 658 failed in aggregate ,166 in aggregate and in group1 434 in aggregate and in group2 372 in group1 590 in group 2 and 126 in both the groups. how many failed in aggregate but not in group 2? a)106 b)224 c)206 d) 464​

Answers

Answered by knjroopa
4

Step-by-step explanation:

Given out of 1000 student 658 failed in aggregate ,166 in aggregate and in group 1 434 in aggregate and in group 2 372 in group 1  590 in group 2 and 126 in both the groups. how many failed in aggregate but not in group 2?

  • Let A, B and C be three sets.
  • So number of elements of A n(A) = 658
  • So number of elements of B n(B) = 590
  • So number of elements of C n(C ) = 372
  • Now n(A Ո B) = 434
  • So n (B Ո C) = 126
  • So n (C Ո A) = 166
  • So n (A U B U C) = 1000
  • n (A U B U C)  = n(A) + n(B) + n(C) – n (A Ո B) – n (B Ո C) – n (C Ո A) +  n (A Ո B Ո C)
  •          1000 = 658 + 590 + 372 – 434 – 126 – 166 + n (A Ո B Ո C)
  •          1000 = 894 + n (A Ո B Ո C)
  •              1000 - 894 = n (A Ո B Ո C)
  •         Or n (A Ո B Ո C) = 106

Reference link will be

https://brainly.in/question/5793376

Answered by shahanaaz90
3

Answer:

option A. 106will be the correct answer hope it helps you

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