Question

Out of 1900 km, Vishal travelled some distance by bus and some by aeroplane.

Bus travels with average speed 60 km/hr and the average speed of aeroplane is

700 km/hr. It takes 5 hours to complete the journey. Find the distance, Vishal

travelled by bus.​

Answer 1

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Answer 2

$\large\underline\bold{Solution}$:-

$\rm{Total \: distance \: = \: 1900 \: km}$

$\rm{let \: , \: Distance \: travelled \: by \: bus \: be \: x \: km \: .}$

$\rm{So \: , \: distance \: travelled \: by \: aeroplane \: will \: be \: (1900 - x) \: km \: .}$

$\rm{Time \: taken \: to \: cover \: the \: distance \: of \: 1900 \: km \: = \: 5 \: hours}$

$\rm{As \: per \: question \: ,}$

$\rm{\: \: \: \: \dfrac{x}{60} + \dfrac{(1900 - x)}{700} \: = \: 5}$

$\rm{\: \: \dfrac{x}{60} + \dfrac{1900}{700} - \dfrac{x}{700} \: = \: 5}$

$\rm{\: \: \: \: \dfrac{10x}{600} + \dfrac{19}{7} - \dfrac{x}{700} \: = \: 5}$

$\rm{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \dfrac{10x}{600} - \dfrac{x}{700} \: = \: \bigg(5 - \dfrac{19}{7}\bigg)}$

$\rm{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\dfrac{(70x - 6x)}{4200} \: = \: \dfrac{(35 - 19)}{7}}$

$\rm{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \dfrac{64x}{4200} \: = \: \dfrac{16}{7}}$

$\rm{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \dfrac{64x}{600} \: = \: 16}$

$\rm{\: \: \: \: \: \dfrac{4x}{600} = 1}$

$\rm{\: \: \: \: \: \: \: \: \: \: \dfrac{x}{150} \: = \: 1}$

$\rm{\: \: \: \: \: \: \: \: x \: = \: 150 \: km}$

$\rm{So \: , \: the \: distance \: travelled \: by \: bus \: is \: 150 \: km.}$