out of 1900 km vishal travelled some distance by bus and some by aeroplane bus travels with average speed 60 km /hr and the average speed of aeroplane is 700 km/hr it takes 5 hrs to complete the journey find the distance vishal travelled by bus
Answers
Answered by
259
Let the distance traveled by bus = x
Time taken traveling by bus = x/60
Distance traveled by plane = (1900-x)
Time taken traveling by plane = (1900-x)/700
Total time = x/60 + (1900-x)/700 = 5
x/60 – x/700 = 16/7
8/525x = 16/7
x = 150
Therefore, the distance traveled by bus = 150km
Time taken traveling by bus = x/60
Distance traveled by plane = (1900-x)
Time taken traveling by plane = (1900-x)/700
Total time = x/60 + (1900-x)/700 = 5
x/60 – x/700 = 16/7
8/525x = 16/7
x = 150
Therefore, the distance traveled by bus = 150km
Answered by
122
We know that the total distance travelled by Vishal is 1900 km.
Therefore let's assume the distance travelled by bus is x km.
And the distance travelled by plane is (1900-x)km.
Again we know the total time taken by him to complete the journey is 5 hrs.
Therefore let us assume that time taken while travelling in bus is y hrs.
And time taken while travelling in plane is (5-y)hrs.
We have,
Speed of bus=60km/hr
Speed of plane=700km/hr.
We know,
Distance=speed*time
For bus,
X=60*y-------------eqn (1)
For plane,
(1900-x)=700*(5-y)-------------eqn(2)
Solving these two equations we get x=150
i.e The distance travelled by bus is 150 km
Therefore let's assume the distance travelled by bus is x km.
And the distance travelled by plane is (1900-x)km.
Again we know the total time taken by him to complete the journey is 5 hrs.
Therefore let us assume that time taken while travelling in bus is y hrs.
And time taken while travelling in plane is (5-y)hrs.
We have,
Speed of bus=60km/hr
Speed of plane=700km/hr.
We know,
Distance=speed*time
For bus,
X=60*y-------------eqn (1)
For plane,
(1900-x)=700*(5-y)-------------eqn(2)
Solving these two equations we get x=150
i.e The distance travelled by bus is 150 km
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